8^(2y+4)=16y+1

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Solution for 8^(2y+4)=16y+1 equation: 



8^(2y+4)=16y+1

We move all terms to the left:

8^(2y+4)-(16y+1)=0

We get rid of parentheses

8^(2y+4)-16y-1=0

We add all the numbers together, and all the variables

-16y+8^(2y+4)-1=0

We move all terms containing y to the left, all other terms to the right

-16y+8^(2y+4)=1

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